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§4.8 Green’s Theorem                                                                                                     149

                                   ()
Proof 2. Let F(x, y, z) = M (x, y), N (x, y), 0 be a vector-valued function defined in a

subset of R3. Then

                                         curlF = (0, 0, Nx ´ My) ;

thus the Stokes theorem implies that

¿ żż ż

(M, N ) ¨ dr = F ¨ T ds = curlF ¨ N dS = (0, 0, Nx ´ My) ¨ (0, 0, 1) dA

BD BD D                                                                        D

                     ż

                    = (Nx ´ My) dA .                                                                                            ˝

                         D

Proof 3. Let Σ = D ˆ tz = 0u. Then Σ is a surface with boundary and the upward-

pointing unit normal N = (0, 0, 1(). Let F : Σ Ñ R3 and u : D Ñ (R2 be vector-value)d
functions defined by F(x, y, z) = N (x, y), ´M (x, y), 0) and u(x, y) = N (x, y), ´M (x, y) ,

respectively. We note that if B D is parameterized by r(t) = (x(t), y(t), 0), then

T          ˆ  N  =       1       (   1(t),  y  1  (t),   )  ˆ  (0, 0, 1)  =       1       (   1  (t),  ´x  1(t),   )  ;
                        1(t)}R3   x                     0                        1(t)}R3   y                      0
                    }r                                                       }r

thus by the fact that the surface divergence operator divΣ is the same as the 2-d divergence

operator (since Σ is flat), Theorem 4.83 implies that

¿¿                                                      ż żż

(M, N ) ¨ dr = F ¨ (T ˆ N) ds = divΣF dS = divu dA = (Nx ´ My) dA . ˝

BD BD                                                       Σ DD

Corollary  4.91.    Let  R (Ď    R2  be     a     domain       enclosed    by  a  simple      closed   curve      C      which  is
                                            )
parameterized by r(t) = x(t), y(t) for t P [a, b]. Suppose r 1 points in the counter-clockwise

direction. Then                                         żb   [                          ]
                                                              x(t)y           y(t)x1(t) dt
                         the  area   of     R=    1       a          1(t)  ´                     .
                                                  2

Proof. The corollary is concluded by applying Green’s theorem to the special case: M (x, y) =

´y and N (x, y) = x.                                                                                                            ˝

Example 4.92. Compute the area enclosed by the Cardioid which has a polar representa-

tion r = (1 ´ sin θ) with θ P [0, 2π].                         y

                                                                                  x

                                     Figure 4.7: The Cardioid
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