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74 CHAPTER 3. Multiple Integrals

all sets of sample points tξ1, ¨ ¨ ¨ , ξN u for P, we must have

                                     ˇ   N   f A(ξk)ν(∆k)             ˇ         ε
                                     ˇ                               Iˇ         4
                                     ˇ  ÿ
                                                                      ˇ
                                                                ´        ă         .

                                        k=1

Let P = t∆1, ¨ ¨ ¨ , ∆N ( be a partition of A with }P} ă δ. Choose two sample sets
tξ1, ¨ ¨ ¨ , ξN u and tη1, ¨ ¨ ¨ , ηN u for P such that

(a)    sup f A(x) ´      ε      ă f A(ξk) ď sup f A(x);
                      4ν(R)
       xP∆k                                            xP∆k

(b)    inf f A(x) +      ε      ą f A(ηk) ě inf f A(x).
                      4ν(R)                            xP∆k
       xP∆k

Then

           U (f,  P)  =   N    sup   f A(x)ν(∆k)     ă     N    [    A  (ξk  )  +         ε     ]   (∆k)
                                                                 f                        (R)    ν
                         ÿ     xP∆k                       ÿ                           4ν

                         k=1                              k=1

                          N    f A(ξk)ν(∆k)             ε        N                    I      ε         ε     I     ε
                                                     4ν(R)                                   4         4           2
                         ÿ                                      ÿ

                      =                         +                    ν(∆k)         ă      +      +        =     +

                         k=1 k=1

and

       L(f,   P)  =    N     inf   f A(x)ν(∆k)       ą     N    [   A  (ηk  )  ´         ε    ]           )
                                                                 f                       (R)   ν(∆k
                      ÿ      xP∆k                         ÿ                        4ν

                      k=1                                 k=1

                          N  f A(ηk)ν(∆k)               ε        N                    I      ε         ε     I     ε
                                                     4ν(R)                                   4         4           2
                         ÿ                                      ÿ

                  =                             ´                   ν(∆k)       ą        ´      ´         =     ´     .

                      k=1 k=1

As  a  consequence,   I  ´   ε  ă  L(f, P)      ď  U (f, P)     ă    I  +   ε;     thus   U (f,     P)    ´  L(f,     P)  ă  ε.
                             2
                                                                            2

                   ż

“ñ” Let I = f (x)dx, and ε ą 0 be given. Since f is Riemann integrable over A, there

           A                                                                                 ε.

exists a partition P1 of A such that U (f, P1) ´ L(f, P1) ă                                  2    Suppose that P1(i) =

␣y0(i), y1(i), ¨ ¨ ¨ , ym(i)i( for 1 ď i ď n. With M denoting the number m1 + m2 + ¨ ¨ ¨ + mn,

we define

                         δ  =                     (          ε                                 )    .
                                                n)                                            1
                                4rn´1(M      +       sup  f  A  (R)  ´   inf f A(R)       +

Then δ ą 0. Our goal is to show that if P is a partition of A with }P} ă δ and

tξ1, ¨ ¨ ¨ , ξN u is a set of sample points for P, then (3.2) holds.

      Assume that P = t∆1, ∆2, ¨ ¨ ¨ , ∆N u is a given partition of A with }P} ă δ.
Let P1 be the common refinement of P and P1. Write P1 = t∆11, ∆21 , ¨ ¨ ¨ , ∆N1 1u and
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