Page 44 - Vector Analysis
P. 44

40 CHAPTER 2. Differentiation of Functions of Several Variables

Definition 2.23. Let U Ď Rn be an open set, and f : U Ñ Rm. The matrix

                        B f1             ¨¨¨       B f1                      B f1 (x)   ¨¨¨     B f1 (x)  
                                          ...       B xn    (x) ”              ...               
              (Jf )(x) ”     B x1                                         B x1               B xn
                                          ¨¨¨         ...                                  ¨¨¨
                                     ...                                            ...                ...
                                                    B fm
                                   B fm                                         B fm (x)           B fm (x)

                                   B x1             B xn B x1                                      B xn

is called the Jacobian matrix of f at x (if each entry exists).

Remark 2.24. A function f might not be differential even if the Jacobian matrix Jf exists;
however, if f is differentiable at x0, then (Df )(x) can be represented by (Jf )(x); that is,
[(Df )(x)] = (Jf )(x).

Example 2.25. Let f : R2 Ñ R3 be given by f (x1, x2) = (x21, x13x2, x14x22). Suppose that f

is differentiable at x = (x1, x2), then

                                                               2x1             
                                                               3x12x2     0
                                      []               =   
                                       (Df )(x)                           x13  .
                                                                        2x41x2
                                                               4x31x22

Remark 2.26. For each x P A, Df (x) is a linear transformation, but Df in general is not

linear in x.

Example 2.27. Let f : R2 Ñ R be given by

                                               # xy               if (x, y) ‰ (0, 0) ,
                                   f (x, y) = x2 + y2

                                                       0 if (x, y) = (0, 0) .

Then    Bf  (0, 0)  =  B f (0, 0)  =  0;  thus  if  f  is  differentiable       at  (0, 0),   then  (Df )(0, 0)      =  [    ]
                                                                                                                         0  0.
        Bx By
However,

              ˇ[                                 ]  []      ˇ  =    |xy|        =       |xy|       ax2   + y2 ;
              ˇf (x, y) ´ f (0, 0) ´ 0          0    x      ˇ     x2 + y2
              ˇ                                      y      ˇ                      (x2     y2)  3
                                                                                        +       2

thus f  is not differentiable at (0, 0) since               |xy|        cannot be arbitrarily small even if x2+y2

                                                       (x2  +  y2)  3
                                                                    2

is small.

Example 2.28. Let f : R2 Ñ R be given by

                                                     $ x if y = 0 ,
                                                     &
                                        f (x, y) = y if x = 0 ,
                                                     % 1 otherwise .
   39   40   41   42   43   44   45   46   47   48   49