Page 46 - Vector Analysis
P. 46

42 CHAPTER 2. Differentiation of Functions of Several Variables

Theorem 2.30. Let U Ď Rn be open, a P U , and f : U Ñ R. If
   1. the Jacobian matrix of f exists in a neighborhood of a, and

    2. at least (n ´ 1) entries of the Jacobian matrix of f are continuous at a,

then f is differentiable at a.

Proof.    W.L.O.G. we can assume that                                                    Bf ,       Bf       ,     ¨  ¨  ¨  ,    Bf              are continuous at a.                          Let tejunj=1
                                                                                                    B x2                       B xn´1
                                                                                         B x1
be the standard basis of Rn, and ε ą 0 be given. Since B f is continuous at a for i =
                                                                                                                                                 B xi
1, ¨ ¨ ¨ , n ´ 1,

                               D δi     ą     0     Q     ˇ  Bf          (x)      ´   Bf      ˇ     ă         ε          whenever                }x ´ a}Rn                     ă   δi .
                                                          ˇ  B xi                          (a)ˇ              ?
                                                          ˇ                           B xi ˇ
                                                                                                               n

On the other hand, by the definition of the partial derivatives,

                      D δn     ą     0  Q     ˇ  f  (a       +     hen)        ´  f   (a)  ´        Bf       ˇ           ă      ε          whenever                   0     ă  |h|    ă  δn .
                                              ˇ                                                           (a)ˇ                 ?

                                              ˇh                                                 B xn ˇ                          n

Let k = x ´ a and δ = min ␣δ1, ¨ ¨ ¨ , δn(. Then

    ˇ                                      [ Bf                                                           Bf                                        ]ˇ
    ˇf (x)                                                                                                B xn
    ˇ              ´     f  (a)      ´      B x1       (a)(x1                  ´  a1)  +   ¨  ¨  ¨  +                 (a)(xn            ´     an)      ˇ
                                                                                                                                                       ˇ

                   =  ˇ           +     k)       ´     f (a)          ´        Bf     (a)k1   ´     ¨  ¨  ¨  ´        Bf       (a)kn          ˇ
                      ˇf (a                                                    B x1                                   B xn                    ˇ
                      ˇ                                                                                                                       ˇ

                      ˇ                                                                                                              Bf                                            Bf            ˇ
                                                                                                                                     B x1                                          B xn          ˇ
                   =  ˇf    (a1      +     k1,      ¨  ¨  ¨     ,  an       +     kn)  ´   f (a1,      ¨  ¨  ¨  ,     an)      ´                 (a)k1       ´        ¨  ¨  ¨  ´         (a)kn   ˇ
                      ˇ

                      ˇ                                                                                                                                                  Bf              ˇ
                                                                                                                                                                         B x1      (a)k1ˇˇ
                   ď  ˇf    (a1      +     k1,      ¨  ¨  ¨     ,  an       +     kn)  ´   f (a1,      a2     +       k2,      ¨  ¨  ¨  ,  an    +     kn)         ´
                      ˇ

                            ˇ                                                                                                                                                            Bf          ˇ
                                                                                                                                                                                         B x2  (a)k2ˇˇ
                      +     ˇf    (a1,     a2       +     k2,         ¨  ¨  ¨  ,  an  +   kn)    ´     f (a1,         a2,      a3       +  k3,      ¨  ¨  ¨  ,  an       +     kn)    ´
                            ˇ

                                           ˇ                                                                                                              Bf                ˇ
                                                                                                                                                          B xn        (a)knˇˇ
                      +     ¨  ¨  ¨  +     ˇf    (a1      ,  ¨  ¨  ¨     ,  an´1,     an   +  kn)      ´      f (a1,           ¨  ¨  ¨  ,  an)      ´                              .
                                           ˇ

By the mean value theorem,

          f (a1, ¨ ¨ ¨ , aj´1, aj + kj, ¨ ¨ ¨ , an + kn) ´ f (a1, ¨ ¨ ¨ , aj, aj+1 + kj+1, ¨ ¨ ¨ , an + kn)

                      =     kj    Bf          (a1,     ¨     ¨  ¨  ,     aj´1,    aj   +   θj kj ,     aj+1           +     kj+1,       ¨  ¨  ¨  ,  an       +     kn)
                                  B xj

for some 0 ă θj ă 1; thus for j = 1, ¨ ¨ ¨ , n ´ 1, if }x ´ a}Rn = }k}Rn ă δ,

ˇ                                                                                                                                                                                              Bf            ˇ
                                                                                                                                                                                               B xj
ˇf  (a1,  ¨  ¨  ¨  ,  aj´1,       aj    +     kj ,     ¨  ¨  ¨     ,  an       +  kn)  ´   f (a1,         ¨¨    ¨  ,  aj ,     aj+1        +     kj+1,          ¨  ¨  ¨     ,  an  +  kn)   ´         (a)kj  ˇ
ˇ                                                                                                                                                                                                            ˇ

    =           ˇ  Bf    (a1,              , aj´1, aj                 +        θjkj, aj+1     +     kj+1, ¨ ¨ ¨                , an     +     kn)            Bf             ˇ               ε    |kj     .
                ˇ  B xj           ¨  ¨  ¨                                                                                                              ´     B xj        (a)ˇˇ|kj |      ď  ?         |
                ˇ                                                                                                                                                                             n
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