Page 18 - Vector Analysis
P. 18

14 CHAPTER 1. Linear Algebra

1. Switching the i0-th and j0-th rows of A, where i0 ‰ j0, is done by left multiplied A
   by the matrix E = [eij]nˆn given by

        "                        1    if (i, j) = (i0, j0) or (i, j) = (j0, i0) or i = j = k0 for some k0 ‰ i0, j0,
                                 0    otherwise,
eij  =

or in the matrix form,

         1 0 ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨                                                                              0
                                                                                                                           ...
          0    ...                      0    ...                                                    ...  
                                 ...  ...                      1    0                                                      ...
                                 ...                           0    ...                                                    ...
                                 ...                                     0              1                                  ...                           Ð the  i0-th  row
E    =                           ...                                1    1    ...  0                                       ...                           Ð the  j0-th  row
                                 ...                                     0    ...  1    ...                                ...
                                 ...                                          ...  0    0                                  ...
                                 0                                                      ...                                0
                                 0                                                           0    ...
                                                                                             1    ...
                                                                                             0

                                 0 ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ 0                                                       1

                                                                    ÒÒ

                                                               the i0-th column the j0-th column

2. Multiplying the k0-th row of A by a non-zero scalar λ is done by left multiplied A by

   the matrix E = [eij]nˆn given by

                                                 $ 0 if i ‰ j,
                                                 &
                                          eij = λ if i = j = k0,
                                                 % 1 otherwise,

or in the matrix form,
                                      
                                                          1 0 ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ 0
                                                                                ...  
                                                          0    1    0    ...                      ...
                                                          ...  ...  ...  1                        ...
                                                          ...            0                        ...
                                                          ...       0         0                   ...
                                                          ...                 λ                   ...
        E                        =                        ...                 0    0              0                        Ð    the                      k0-th  row
                                                          ...
                                                                                   1    0    ...
                                                                                   ...  ...  1

                                                                                        0

                                                          0 ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ ¨¨¨ 0 1
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